this post was submitted on 14 Aug 2024
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Today I Learned

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[–] FundMECFSResearch@lemmy.blahaj.zone 3 points 2 months ago (1 children)

What about if you add the sun into the equation?

[–] prime_number_314159@lemmy.world 32 points 2 months ago (2 children)

If you take the sun out of the equation, the planets fly apart in all directions. Hope that helps ;)

[–] FundMECFSResearch@lemmy.blahaj.zone 3 points 2 months ago (2 children)

I mean would the planets be closer to mercury or the sun on average

[–] Kethal@lemmy.world 13 points 2 months ago* (last edited 2 months ago) (1 children)

By the reasoning given for why Mercury is the closest for each planet, the Sun is the closest object for each planet, on average, excluding satellites of the planets.

[–] mecfs@lemmy.world 1 points 2 months ago (1 children)

I would agree but unsure because there are the intricacies of orbit cycles and timings and the 3d plane of space

[–] rockerface@lemm.ee 4 points 2 months ago

I mean, the Solar System isn't all that 3D. Inside of the Oort Cloud, almost every notable object is on or close to the ecliptic

[–] NJSpradlin@lemmy.world 1 points 2 months ago* (last edited 2 months ago) (1 children)

I am not a scientist, or mathematician, or STEM in any way, but if we assume that mercury has a circular orbit, and the sun has a stationary position within everyone’s orbit… and that every planet has a circular orbit, instead of elliptical, then we can assume… that the sun and mercury (edit: or ANY planet) are equal, since mercury is half of the time further and half of the time closer.

I hope that helps. I know the first rule of the internet is that stating something wrong will immediately result in being corrected by a SME, so either way my comment will get you* the correct answer.

Edit: this reasoning would only apply to planets that have circular orbits and are on the same plane.

[–] FundMECFSResearch@lemmy.blahaj.zone 6 points 2 months ago* (last edited 2 months ago) (1 children)

Thanks for the attempt but your calculation is wrong, as it considers distance only on a one axis and not a two axis plane. With your circle assumption, mercury would be further than the sun on average.

I wonder if anyone has the data without the circle assumption, and also correcting for the various other complexities.

[–] NJSpradlin@lemmy.world 2 points 2 months ago (1 children)

Thanks, you fell into the trap. But, how would Mercury be further on average if we assumed circular orbits and the planets were on the same plane?

[–] mecfs@lemmy.world 8 points 2 months ago (1 children)

hope my shitty drawing helps

(replying from my alt)

[–] NJSpradlin@lemmy.world 4 points 2 months ago* (last edited 2 months ago)

Your bar napkin math has convinced me.

Edit: original commenter, here is your answer.

[–] eyeon@lemmy.world 2 points 2 months ago

I don't think that would help, I quite like our relative location.