this post was submitted on 08 Dec 2023
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Advent Of Code

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An unofficial home for the advent of code community on programming.dev!

Advent of Code is an annual Advent calendar of small programming puzzles for a variety of skill sets and skill levels that can be solved in any programming language you like.

AoC 2023

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Day 8: Haunted Wasteland

Megathread guidelines

  • Keep top level comments as only solutions, if you want to say something other than a solution put it in a new post. (replies to comments can be whatever)
  • Code block support is not fully rolled out yet but likely will be in the middle of the event. Try to share solutions as both code blocks and using something such as https://topaz.github.io/paste/ , pastebin, or github (code blocks to future proof it for when 0.19 comes out and since code blocks currently function in some apps and some instances as well if they are running a 0.19 beta)

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[โ€“] mykl@lemmy.world 2 points 11 months ago* (last edited 11 months ago)

Dart

Part 1 was easy enough. For Part 2 I took a guess that the cycles were all well behaved and I could get away with just calculating the LCM, and it paid off.

(List, Map) parse(List lines) => (
      lines.first.split(''),
      {
        for (var l in lines.skip(2).map((e) => e.split(RegExp(r'[^A-Z0-9]'))))
          l[0]: [l[4], l[6]]
      }
    );
int movesTo(pos, steps, rules) {
  var stepNo = -1;
  while (!pos.endsWith('Z')) {
    pos = rules[pos]![steps[(stepNo += 1) % steps.length] == 'L' ? 0 : 1];
  }
  return stepNo + 1;
}

part1(List lines) {
  var (steps, rules) = parse(lines);
  return movesTo('AAA', steps, rules);
}

// All cycles are independent of state of `steps`, and have
// first instance == cycle length which makes this verrry simple.
part2(List lines) {
  var (steps, rules) = parse(lines);
  return [
    for (var start in rules.keys.where((e) => e.endsWith('A')))
      movesTo(start, steps, rules)
  ].reduce((s, t) => s.lcm(t));
}
}