this post was submitted on 16 May 2024
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    [–] Abnorc@lemm.ee 30 points 5 months ago (6 children)

    Almost. 1/x approaches infinity from the positive direction, but it approaches negative infinity from the negative direction. Since they approach different values, you can't even say the limit of 1/x is infinity. It's just undefined.

    [–] NeatNit@discuss.tchncs.de 6 points 5 months ago (4 children)

    https://en.wikipedia.org/wiki/Division_by_zero#Floating-point_arithmetic

    In IEEE arithmetic, division of 0/0 or ∞/∞ results in NaN, but otherwise division always produces a well-defined result. Dividing any non-zero number by positive zero (+0) results in an infinity of the same sign as the dividend. Dividing any non-zero number by negative zero (−0) results in an infinity of the opposite sign as the dividend. This definition preserves the sign of the result in case of arithmetic underflow.

    [–] Bumblefumble@lemm.ee 0 points 5 months ago (3 children)

    10/0 ≠ lim x->0+ 10/x

    Or in other words, the thing you keep quoting does not apply in this case. Any number divided by zero is undefined, not positive infinity (or negative infinity for that matter).

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